Ch 7. Rigid Body Energy Methods Multimedia Engineering Dynamics Rot. Work & Energy Conservation of Energy
 Chapter - Particle - 1. General Motion 2. Force & Accel. 3. Energy 4. Momentum - Rigid Body - 5. General Motion 6. Force & Accel. 7. Energy 8. Momentum 9. 3-D Motion 10. Vibrations Appendix Basic Math Units Basic Equations Sections Search eBooks Dynamics Statics Mechanics Fluids Thermodynamics Math Author(s): Kurt Gramoll ©Kurt Gramoll

 DYNAMICS - CASE STUDY SOLUTION Problem Graphic   Problem Diagram The Principle of Work and Energy for a rotating body can be applied to this problem using      T1 + ΣU1-2 = T2 The applied work for a constant moment is      U = M θ = (100 N-m) (4.459 rad)         = 445.9 N-m Now the input energy is known, the change in kinetic energy needs to be determined,      Tstart = T1 = 0      Tfinish = T2 = 1/2 m vG2 + 1/2 IG ω2               = 0 + 0.5 IG (1.784 rad/s)2              = (1.591 /s2) IG Equating the work done to the change in kinetic energy gives      0 + 445.9 N-m = (1.591 /s2) IG Solving for IG gives      IG = Iz = 280.3 kg-m2

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